Skip to main content

Bresenham Circle Algorithm Implementation in C



# include<stdio.h>
# include<conio.h>
# include<graphics.h>

void main()
{
 int gd=DETECT,gm;
 int r,x,y,p,xc=320,yc=240,i;

 initgraph(&gd,&gm,"..\\BGI");

 printf("Enter the radius ");
 scanf("%d",&r);

 for(i=0;i<10;i++);
 {
 x=0;
 y=r;
 //putpixel(xc+x,yc-y,15);

 p=3-(2*r);

 for(x=0;x<=y;x++)
 {
 if (p<0)
 {
  y=y;
  p=(p+(4*x)+6);
 }
 else
 {
  y=y-1;

  p=p+((4*(x-y)+10));
 }

 putpixel(xc+x,yc-y,15);
 putpixel(xc-x,yc-y,15);
 putpixel(xc+x,yc+y,15);
 putpixel(xc-x,yc+y,15);
 putpixel(xc+y,yc-x,15);
 putpixel(xc-y,yc-x,15);
 putpixel(xc+y,yc+x,15);
 putpixel(xc-y,yc+x,15);

 }

 r=r-10;
 //xc=xc-5;
 //yc=yc-5;
 }
 getch();
 closegraph();
}


Comments

Popular posts from this blog

Use Case Diagram for Online Book Store

Occurrences of each letter of alphabet in the text

Program to print a table indicating the no. of occurrences of each letter of alphabet in the text entered as command line arguments. #include<iostream> #include<string> using namespace std; int main(int argc, char *argv[]) { string str=""; static int alphabet[26]; int x; cout<<"\n\n Command-Line Argument\n"; for(int i=0;i<argc;i++) { cout<<"\n "<<argv[i]; str+=argv[i]; } for(int i=0;i<str.length();i++) { if(str[i]>='A' && str[i]<='Z') { x=((int)str[i])-65; alphabet[x]++; } else if(str[i]>='a' && str[i]<='z') { x=((int)str[i])-97; alphabet[x]++; } } //Displaying No. of occurrences of each alphabets in the command line argument cout<<"\n\n~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\n Alphabet No. of Occurrences\n~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~"; for(int i=0;i<26;i++)...

Linear search & Binary search using Template

Write a program to search an element from a list. Give user the option to perform Linear or Binary search. Use Template functions. #include<iostream> using namespace std; template <class T> void Lsearch(T *a, T item, int n) { int z=0; for(int i=0;i<n;i++) { if(a[i]== item) { z=1; cout<<"\n Item found at position = "<<i+1<<"\n\n"; } else if(z!=1) { z=0; } } if(z==0) cout<<"\n Item not found in the list\n\n"; } template <class T> void Bsearch(T *a, T item, int n) { int beg=0,end=n-1; int mid=beg+end/2; while((a[mid]!=item) && (n>0)) { if(item>a[mid]) beg=mid; else end=mid; mid=(beg+end)/2; n--; } if(a[mid]==item) cout<<"\n Item found at position = "<<mid+1<<"\n\n"; else cout<<"\n Item not found in the list\n\n"; } void main() { int iarr[10] = {2,42,56,86,87,99,323,546,767,886};...